Subject: RE: How to use xslt to transform xml to xml with added nodes From: Mike Brown <mbrown@xxxxxxxxxxxxx> Date: Mon, 20 Sep 1999 11:26:24 -0600 |
> if textg = "xxxx", or "yyyyyyyy" or "zz" then texti = "something" > if textg = "aaaa", or "bb" or "cccccccccccc", or "d" or "eee" > then texti = "something else" > [...] > Can this be done with a transform without a huge <xsl:choose>. You could put the string mappings in the XML, as a kind of lookup table. <StringMap> <texti out="something"> <textg>xxxxx</textg> <textg>yyyyy</textg> <textg>zz</textg> </texti> <texti out="something else"> <textg>aaaa</textg> <textg>bb</textg> <textg>cccccccccccc</textg> </texti> </StringMap> Then you could do this, given string $textg: <xsl:variable name="texti" select="string(/StringMap/texti[textg=$textg]/@out)"/> XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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