RE: if confusion

[Ben Robb <Ben@xxxxxxxxxx>]

Your <xsl:when> should read:

<xsl:when test="../TYPE[.=1]">

Rgs,

Ben


> -----Original Message-----
> From: Sargeant, Richard (GEIS) [mailto:Richard.Sargeant@xxxxxxxxxxx]
> Sent: 21 September 1999 12:01
> To: xsl-list@mulberrytech. com (E-mail)
> Subject: xsl:if confusion
> 
> 
> Hi,
> 
>    While processing a node I need to do conditional 
> processing based on the
> contents of another node of the same parent. For example my 
> XML looks like
> 
>    <USER>
>       <TYPE>1</TYPE>
>       <PASSWORD>pwd</PASSWORD>
>    </USER>
> 
>  The xsl for node password is
> 
>    <xsl:template match="PASSWORD">
>       <td>
>          <font face="arial" size="2">Password: </font>
>          <font face="arial" size="2" color="#000080">
>          <xsl:choose>
>             <xsl:when test="../TYPE=1">########</xsl:when>
>             <xsl:otherwise>
>                <xsl:value-of select="."/>
>             </xsl:otherwise>
>          </xsl:choose>
>          </font>
>       </td>
>    </xsl:template>
> 
> I've also tried ../TYPE/text()='1' but that also fails. What 
> I'm I doing
> wrong ?
> 
> regards
>    Richard
> 
> 
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> 


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