<xsl:choose>

[Zvi Avraham <zvia@xxxxxxxxxxxxxxx>]

Hi People,

I have stock database in my XML source:

 <stocks>
  <stock symbol="PHCM" price="$142.75" change="+7.75"
volume="2,000,000"/>
  <stock symbol="ALA" price="$29.12" change="-1.25" volume="345,000"/>
  <stock symbol="ERICY" price="$31.00" change="+5.12" volume="990,000"/>

  <stock symbol="NOK" price="$87.06" change="+3.92" volume="1,234,000"/>

  <stock symbol="MOT" price="$91.00" change="-1.00" volume="1,000,000"/>

  <stock symbol="IRIQE" price="$4.25" change="0.00" volume="0"/>
 </stocks>

I want to render it in table, when earning change will be green, and
looses will be red...
I using next XSLT fragment, but seems, that no mutter whats change is,
XSLT always render
<xsl:otherwise> part ...

<xsl:stylesheet xmlns:xsl="http://www.w3.org/XSL/Transform/1.1";>

[snip]

 <xsl:choose>
  <xsl:when test="number(@change) &gt; 0">
   <font face="Arial,Helvetica" size="1" color="green">
    <xsl:value-of select="@change"/>
   </font>
  </xsl:when>
  <xsl:when test="number(@change) &lt; 0">
   <font face="Arial,Helvetica" size="1" color="red">
    <xsl:value-of select="@change"/>
   </font>
  </xsl:when>
  <xsl:otherwise>
   <font face="Arial,Helvetica" size="1">
    <xsl:value-of select="@change"/>
   </font>
  </xsl:otherwise>
 </xsl:choose>

[snip]

I tried so many things, with/out number() function, using xsl:variable
etc ...

Any ideas ?

Thanks in advance
Zvi


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