Re: replacing characters in a string

Subject: Re: replacing characters in a string
From: Edd Dumbill <edd@xxxxxxxxxxxxx>
Date: Fri, 15 Oct 1999 14:13:14 +0000

On Fri, Oct 15, 1999 at 01:33:02PM +0100, David Carlisle wrote:
> 
> >  see if there's an apostrophe character, if so, convert this
> > to \', if not, just output the value of 'name'.
> 
> 
> something like this?
> 
> David
> 
[ 20-odd lines of code elided ]

This looks like a task XSLT doesn't do very well.  Does anyone's XSLT
processor have a regex extension function in it?  If not, looks like one
that would be a welcome addition...

-- 
Edd

 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list

Current Thread
replacing characters in a string Linda van den Brink - Fri, 15 Oct 1999 13:52:46 +0200 David Carlisle - Fri, 15 Oct 1999 13:33:02 +0100 (BST) Edd Dumbill - Fri, 15 Oct 1999 14:13:14 +0000 <= David Carlisle - Fri, 15 Oct 1999 16:29:55 +0100 (BST) Clark C. Evans - Fri, 15 Oct 1999 12:30:03 -0400 (EDT) Clark C. Evans - Fri, 15 Oct 1999 12:43:32 -0400 (EDT) Clark C. Evans - Fri, 15 Oct 1999 13:09:01 -0400 (EDT)

Current Thread

replacing characters in a string
- Linda van den Brink - Fri, 15 Oct 1999 13:52:46 +0200
  - David Carlisle - Fri, 15 Oct 1999 13:33:02 +0100 (BST)
    - Edd Dumbill - Fri, 15 Oct 1999 14:13:14 +0000 <=
      - David Carlisle - Fri, 15 Oct 1999 16:29:55 +0100 (BST)
      - Clark C. Evans - Fri, 15 Oct 1999 12:30:03 -0400 (EDT)
      - Clark C. Evans - Fri, 15 Oct 1999 12:43:32 -0400 (EDT)
      - Clark C. Evans - Fri, 15 Oct 1999 13:09:01 -0400 (EDT)

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