Re: document(), apply-templates and parameters

Subject: Re: document(), apply-templates and parameters
From: "Tangi Vass" <tangivass@xxxxxxxxxxxxxx>
Date: Thu, 21 Oct 1999 10:45:30 +0200
Scott Boag from Lotus sent me a mail of explanations :
 
"document('foo.xml')" selects the '/' node on foo.xml, which has not template,
so it falls to the default template. Since parameters do not get automatically
passed from template to template, you loose the parameter in the default
template for '/'.  If you do select="document('foo.xml')/*", you will get the
expected results.
Before his help, I found a workaround :
    <xsl:for-each select="document('foo.xml')">
      <xsl:apply-templates>
        <xsl:with-param name="arg1>ok</xsl:with-param>
      </xsl:apply-templates>
    </xsl:for-each>
but without understanding why it works (it doesn't use the default template for '/' ;-)
 
So thanks a lot for your explanations, Scott.
 
Tangi
----- Original Message -----
From: Tangi Vass
Sent: Wednesday, 20 October, 1999 16:01
Subject: document(), apply-templates and parameters

I tried to do this:
 
    <xsl:apply-templates select="document('foo.xml')">
      <xsl:with-param name="arg1">ok</xsl:with-param>
    </xsl:apply-templates>
 
But it fails: arg1's value is ignored.
 
Could someone tell me why ("normal" feature to prevent potential side-effects, bug in LotusXSL 0.18.2, ...) ?
 
Thanks in advance,
 
Tangi
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