Subject: Re: Remove duplicates from a list From: Tim Taylor <ttaylor@xxxxxxxxxx> Date: Fri, 29 Oct 1999 17:20:48 -0400 |
I have a similar, but more complicated problem. Given the following XML snippet: <skill title="java"/> <skill title="perl"/> <skill title="java"/> I would like to transform to: java perl Actually, there's a bit more to this. The source XML is more like: <employee id="ttaylor"> <skill title="java"/> </employee> <employee id="jdoe"> <skill title="perl"/> <skill title="java"/> </employee> And the desired tranformation (order unimportant): <h2>java</h2> <ol> <li>ttaylor</li> <li>jdoe</li> </ol> <h2>perl</h2> <ol> <li>jdoe</li> </ol> However, I already figured out the XSL for generating the list of employees with a skill, given a list of skill nodes. I'm in search of the XSL for the simpler problem stated above, i.e. listing the first occurance of an element for each title attribute. Starting with Clark Evans' example, I have tried variations on the following idea with no success: <xsl:variable name="unique-list" select="//employee/skill[ not (. = following::skill[@title = current()/@title]) ]"/> I'm sure I mustn't be grokking something. I succesfully used a similar approach to generate the list of employees. The following will transform to the desired output, sans removal of skill following the first occurance: <xsl:for-each select="//employee/skill"> <h2><xsl:value-of select="@title"/></h2> <ol> <xsl:for-each select=".|following::skill[@title=current()/@title] <li><xsl:value-of select="parent::employee/@id"/></li> </xsl:for-each> </ol> </xsl:for-each> Also, since this is really a learning excercise of my own creation, I'm really after comprehension more than the solution. Please explain the solution, or provide pointers to information explaining it. Feel free to only address the simpler problem above. I provided the more complicated examples mostly as background info. Much thanks, Tim "Clark C. Evans" wrote: > > <xsl:variable name="unique-list" > select="//state[not(.=following::state)]" /> > > <xsl:for-each select="$unique-list"> > <xsl:value-of select="." /> > </xsl:for-each> > > On Wed, 27 Oct 1999, Minita Jha wrote: > > <location> > > <state>xxxx</state> > > </location> > > > > <location> > > <state>yyyy</state> > > </location> > > > > <location> > > <state>xxxx</state> > > </location> > > > > The desired output is: > > > > xxxx > > yyyy > > > > That is, duplicate values of state should not be printed. > > Can this be done? > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list -- Tim Taylor XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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