Re: Accessing the XML declaration, the namespace-uri() function

Subject: Re: Accessing the XML declaration, the namespace-uri() function
From: Miloslav Nic <nicmila@xxxxxxxx>
Date: Fri, 05 Nov 1999 06:39:15 +0100
XT will do it automatically, if you use 
<xsl:output method='xml'/> (you can forbid this behavior)

Look at 
http://zvon.vscht.cz/HTMLonly/XSLTutorial/Examples/Example85/exampleInOne.html

Dylan Walsh wrote:
> 
> Is it possible to somehow access the attributes of the <?xml
> version="1.0"?> tag? I'm trying to create a stylesheet that will
> generate a HTML view of any XML code, and I'd like it to begin with the
> <?xml version="1.0"?> tag. So I was planning to write out something
> like:
> &lt;?xml
> then insert the attribute names & their values then close the tag:
> ?&gt;
> 
> I've gotten this approach working for other processing instructions, but
> is it possible with the XML declaration, and if so, how? Are they
> attributes of the root node, or does "The XML declaration is not visible
> to the XSL processor" mean it is truly impossible?
> 
> Would it be safe to assume that the declaration is always <?xml
> version="1.0"?> and hard code it, i.e.:
> &lt;?xml version="1.0"?&gt; ?
> 
> Also, does the namespace-uri() function work in XT? The XT webpage says
> that namespace *axes* aren't supported, but what about the function? I
> can't get it to produce anything (using <xsl:value-of
> select="namespace-uri()> ).
> 
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list

-- 
***************************************************************
Dr. Miloslav Nic                        e-mail: nicmila@xxxxxxxx
Department of Organic Chemistry         TEL: +420 2 2435 5012  
ICT Prague (VSCHT Praha)                     +420 2 2435 4118
    				        FAX: +420 2 2435 4288  
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