Re: Visibility of parameters in templates

Subject: Re: Visibility of parameters in templates
From: "Tangi Vass" <tangivass@xxxxxxxxxxxxxx>
Date: Fri, 26 Nov 1999 11:20:47 +0100
I've got no problem with visibility of parameters in LotusXSL 0.18.5.
I can't help you very much as your stylesheet is incomplete and lacks the
definition of the 'Slide' named template.
Are you sure there is no mispelling in the declaration of the 'extension'
parameter?

Tangi

----- Original Message -----
From: <heiko.grussbach@xxxxxxxx>
To: <xsl-list@xxxxxxxxxxxxxxxx>
Sent: Friday, 26 November, 1999 10:13
Subject: Visibility of parameters in templates


>
> Assume I have the following XSL:
>
> <xsl:param name="right" select="//NAVIGATION//RIGHT_ICON/@REF"/>
>
> <xsl:template match="//SLIDE">
>      <xsl:variable name="extension">.html</xsl:variable>
>      <xsl:for-each select="document(@REF)/*">
>           <xsl:call-template name="Slide">
>                <xsl:with-param name="$extension"/>
>                <xsl:with-param name="$right"/>
>           </xsl:call-template>
>      </xsl:for-each>
> </xsl:template>
> </xsl:stylesheet>
>
> Now, inside the Slide template, I can access $right, but not $extension.
Why? Seems that extension is a local variable, but when I call the template
> "Slide", $extension
> should be well defined and not present any problem. So why do I get
VariableReference out of context (in Lotus 0.18.5).
> In this example, I could of course make extension global, but what if
$extension should select something relative to the currently processed SLIDE
> node?
>
> Any ideas?
>
> Regards
>
> Heiko Grussbach
> Heiko.Grussbach@xxxxxxxx
>
>
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