Subject: Re: Using the not function From: David Carlisle <davidc@xxxxxxxxx> Date: Mon, 17 Jan 2000 11:23:16 GMT |
The result of the name() function is the expanded name which consists of a local-part and the namespace URI. Thus two XML documents that are equivalent except for their choice of namespace prefixes will give same answers if the prefixes point to the same namespace URI. Juliane. No, name() gives the literal prefixed name from the source. so if the input is <x xmlns="1"> <a:x xmlns:a="1"/> <b:x xmlns:b="1"/> </x> then all three elements would be the same to self:: but using name() <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0" > <xsl:template match="*"> [<xsl:value-of select="name(.)"/>] <xsl:apply-templates/> </xsl:template> </xsl:stylesheet> gives you [x] [a:x] [b:x] David XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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