Subject: RE: Compare attribute values (fwd) From: Linda van den Brink <lvdbrink@xxxxxxx> Date: Wed, 16 Feb 2000 13:09:49 +0100 |
You should be able to do it like this: <xsl:value-of select="//nameloc[@id = current()/@linkend]"/> Or if you've declared the ID attribute on nameloc as of type ID in a DTD, you can do <xsl:value-of select="//nameloc[id(current()/@linkend)]"/> Linda > -----Original Message----- > From: Jany Quintard [mailto:quintard.j@xxxxxx] > Sent: Wednesday, February 16, 2000 11:44 AM > To: xsl digest > Subject: Compare attribute values (fwd) > > > It seems that my question with same subject was > - unclear > - stupid > - nonsensical > - other possibilites... > > In the hope that the first guess is the good, I will try to > reformulate it > : > When encountering an l element, I want to select an element nameloc > somewhere in the tree, whose ID has the same value as > attribute linkend of > the current one (l). > So, the tries I made failed and I don't see how to express > the selection > condition. > > Any clue. > TIA. Jany. > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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