xsl:variable not suppported

Subject: xsl:variable not suppported
From: "anoop" <anoop.agrawal@xxxxxxxxxxxxxxxx>
Date: Tue, 23 Feb 1999 12:59:22 +0530
i am trying to use xsl:variable / xsl:param but it is giving error in ie5
anybody who have used these may come to rescue :-(

anoop

----- Original Message ----- 
From: Bill Rishel <illusyn@xxxxxxxxxx>
To: <xsl-list@xxxxxxxxxxxxxxxx>
Sent: Wednesday, February 23, 2000 12:07 PM
Subject: Re: Filtering on element name e.g. Author*


> > Doesn't work for me.
> > 
> > This will work with ie5 won't it and it does run of the example.
> > 
> 
> I did it with xt:
> XML:
> <?xml version="1.0"?>
> 
> <top>
> <subscriber_id>nick</subscriber_id>
> <portfolio1>fun</portfolio1>
> <portfolio2>serious</portfolio2>
> </top>
> 
> XSL:
> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
>                 xmlns:xt="http://www.jclark.com/xt";
>                 extension-element-prefixes="xt">
> 
> <xsl:output method="xml" indent="yes" omit-xml-declaration="yes"/>
> <xsl:strip-space elements="*"/>
> 
>   <xsl:template match="/">
>       <xsl:apply-templates />
>   </xsl:template>
>   
>   <xsl:template match="top">
>     <xsl:apply-templates select="*[substring(name(),1,9)='portfolio']"/>
>   </xsl:template>
>    
>   <xsl:template match="top/*"> 
>  <xsl:text>
>  </xsl:text>
>  <xsl:value-of select="name()"/>
>   </xsl:template>
> 
> </xsl:stylesheet>
> 
> OUTPUT:
> 
>         portfolio1
>         portfolio 
> 
> 
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list


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