Subject: RE: grouping every three nodes? From: Joel Hughes <joel@xxxxxxxxxxx> Date: Wed, 23 Feb 2000 21:01:57 -0500 |
Search on "Breaking up is hard to do" There was quite a discussion on just this issue on the weekend. Joel joel@xxxxxxxxxxx -----Original Message----- From: Seth Ladd [mailto:shl6472@xxxxxxxxxxxxxxxxxxx] Sent: Wednesday, February 23, 2000 7:42 PM To: xsl-list@xxxxxxxxxxxxxxxx Subject: grouping every three nodes? Hello, I've searched the FAQ and tutorials, and I can't seem to find an answer to this problem. Actually, I don't think it's possible, but I was hoping someone could lend some advise. demo xml file: <group> <item></item> <item></item> <item></item> <item></item> <item></item> </group> I would love to be able to do this in XSL: <xsl:template match="group"> "grab every three item tags and send to named template" </xsl:template> <xsl:template name="group-of-three"> <td> <ul> <xsl:for-each select="item"> <li><xsl:value-of select="."/></li> </xsl:for-each> </ul> </td> </xsl:template> I'm not sure how to grab every three nodes from a nodeset. I'm trying to build a table for every three items in a list. because of the fact that XSL outputs trees, I'm having a hard time. The following would work, except it's not valid XML <!-- won't work --> <xsl:template match="group"> <table> <tr> <xsl:for-each select="item"> <xsl:if test="(position() mod 3) = 0"> <td> <ul> </xsl:if <xsl:value-of select="."/> <xsl:if test="(position() mod 4) = 0"> </ul> </td> </xsl:if> </xsl:for-each> </tr> </table> </xsl:template> Is there anything that will help me break up a nodeset into a group of three? I've solved my problem by using the hack disable-output-encoding, but I'd like to stay away from that. Thanks for any help or pointers you can give me, Seth XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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