RE: selecting a node without its children

Subject: RE: selecting a node without its children
From: "Selva, Francis" <Francis.Selva@xxxxxxxxxxxxxxx>
Date: Thu, 30 Mar 2000 10:54:33 -0800
You can use @id to get the attribute value in ur XSL like this

<xsl:template match="/">
   <xsl:for-each select="STORY">
     <xsl:for-each select="AUTHOR">
       <xsl:value-of select="@id"/>
     </xsl:for-each> 
   </xsl:for-each> 
</xsl:template>

Francis


> -----Original Message-----
> From: Ben Sorek [mailto:bsorek@xxxxxxxxxxxxx]
> Sent: Thursday, March 30, 2000 6:39 PM
> To: xsl-list@xxxxxxxxxxxxxxxx
> Subject: RE: selecting a node without its children
> 
> 
> This is my XML
> 
> 	<STORY>
> 		<AUTHOR id="xsw">Stephen King</AUTHOR>
> 	</STORY>
> 
> If I have a template
> 
> <xsl:template match="STORY">
> 	....
> </xsl:template>
> 
> how can i get the id attribute of author inside that template?
> 
> 
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
> 


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list


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