Subject: Accessing 2 xml files from one xsl From: "Selva, Francis" <Francis.Selva@xxxxxxxxxxxxxxx> Date: Tue, 18 Apr 2000 16:25:20 -0700 |
I solved the problem by doing this.Im getting the right output.But I want to know whether this is the right way or there is a easy way to do what I need. <xsl:template match="/"> <xsl:apply-templates select="document('bw.xml')"/> </xsl:template> <xsl:template match="/"> all my layout stts </xsl:template> Which one is better?.To create one template match and then giving all the node names in the condition while getting the values or having different templates match for each category? Thanx Francis XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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