RE: rookie xmlt transformation question

Subject: RE: rookie xmlt transformation question
From: Warwick Hunter <warwick.hunter@xxxxxxxxxx>
Date: Thu, 20 Apr 2000 12:23:44 +1000
Title: RE: rookie xmlt transformation question

This should do the trick.

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
   
    <xsl:output method="text"/>

    <xsl:template match="/">

        <xsl:for-each select="//group/name">
            <xsl:variable name="dept" select="node()"/>

            <xsl:for-each select="following-sibling::employee/name">
                <xsl:value-of select="$dept"/>
                <xsl:text>|</xsl:text>
                <xsl:value-of select="node()"/>
                <xsl:text>&#10;</xsl:text>
            </xsl:for-each>
             
        </xsl:for-each>

  </xsl:template>
</xsl:stylesheet>

Warwick.
--
Warwick Hunter                    Compaq Computer Australia
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