Subject: RE: arbitrary sorting (Part IV) From: Kay Michael <Michael.Kay@xxxxxxx> Date: Thu, 20 Jul 2000 15:10:37 +0100 |
> I want to sort my elements (<element > month="Jul">...</element>) in the > same order as in <monthtab>. Note: there's no explizit number given in > monthtab. Any ideas how to solve that? > (perhaps by using position() somehow ...) Tricky, because there's no XPath facility to determine the position of a node relative to its siblings: you can only do this using <xsl:number/>, and you can't invoke XSLT-level operations while computing a sort key. Not until the next Saxon release, anyway, which will allow you to implement external XPath functions in XSLT. But if you you're prepared to go outside the standard, the whole problem becomes very easy! Mike Kay XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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