document() and position()

["Dirk Holstein" <dirk.holstein@xxxxxxxxxxxxxx>]

I have multiple xml files. The XML Stream I get
gives me the path to the xml files and the name
of each xml file.

The output I generate doesn't need any of the xml file.
An attribute in the root tag of every xml file
decide if I need this file or not.

The access to the xml files is something like this:

<xsl:apply-templates select="document(/page/folder)/news[@show = 'true']" />

With this call I get only the xml files which have
the 'show' attribute in the 'news' tag set to 'true'.

But now I need to know the number of the actual file I
read in the template I call. I tried something like this:

<xsl:apply-templates select="document(/page/folder)/news[@show = 'true']">
  <xsl:with-param name="index"><xsl:value-of select="position()"
/></xsl:with-param>
</xsl:apply-templates>

But the index parameter is allways '1'. How can I get
the position? Or is there any other way to get the
number of the actual xml file?

Thanks in advance...

Dirk Holstein
--------------------------------------------
web your vision

doubleSlash Net-Business GmbH
Muellerstr. 12/1
88045 Friedrichshafen

Fon 07541 60 47-102
Fax 07541 60 47-111

www.doubleslash.de
dirk.holstein@xxxxxxxxxxxxxx


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list