Subject: Re: Q XSLT: How to copy elements with XT? From: "Joerg Colberg" <joerg.colberg@xxxxxxxxxxx> Date: Tue, 26 Sep 100 17:37:04 EDT |
Vit, I am copying (x)html, too. Here is the basics of what I do: <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml" indent="yes" omit-xml-declaration="yes"> <xsl:template match="/"> <xsl:apply-templates/> </xsl:template> <xsl:template match=" a | applet | b | big | body | br | caption | cite | code | col | colgroup | dd | div | dl | dt | em | font | form | frame | frameset | head | h1 | h2 | h3 | h4 | h5 | h6 | hr | html | i | iframe | img | link | li | map | meta | noframes | ol | p | param | pre | s | script | small | span | strong | style | sub | sup | td | th | title | tr | tt | ul | var | table "> <xsl:copy> <xsl:copy-of select="@*"/> <xsl:apply-templates/> </xsl:copy> </xsl:template> <!-- ADD YOUR template here --> </xsl:output> </xsl:stylesheet> While this doesn't look too elegant, it copies the html and it does something else with the other stuff. Hope this helps, Joerg _______________________________ Dr. Joerg M. Colberg Econovo Software Inc. joerg.colberg@xxxxxxxxxxx XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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