Re: recursion

["Alex Albu" <xsl@xxxxxxxxxxxxxxx>]

Assuming that the root is identified by iParentID=0 and that in your example
nodes 2 and 4 should be at the same level (since they're both children of
1):

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:strip-space elements="*"/>
<xsl:output method="html" indent="yes"/>

<xsl:key name="rowstruct" match="row" use="@iParentID"/>
<xsl:variable name="nbsp">&#xA0;</xsl:variable>

<xsl:template match="/">
    <!-- start with the root -->
    <xsl:apply-templates select="//row[@iParentID=0]"/>
</xsl:template>

<xsl:template match="row">
    <xsl:param name="indent"/>
    <xsl:value-of select="$indent"/><xsl:value-of select="@ItemID"/><br/>
    <xsl:apply-templates select="key('rowstruct', @ItemID)">
        <xsl:with-param name="indent" select="concat($indent, $nbsp)"/>
    </xsl:apply-templates>
</xsl:template>

</xsl:stylesheet>


Hope this helps,
Alex

----- Original Message -----
From: "Oscar Gonzalez" <oscar.gonzalez@xxxxxxxxxxx>
To: <xsl-list@xxxxxxxxxxxxxxxx>
Sent: Wednesday, October 11, 2000 6:32 AM
Subject: recursion


> I have an XML structure like that:
>
> <row ItemID="1" iParentID="0" szSubject="Msg1"/>
>
> <row ItemID="2" iParentID="1" szSubject="Msg2"/>
>
> <row ItemID="3" iParentID="2" szSubject="Msg3"/>
>
> <row ItemID="4" iParentID="1" szSubject="Msg4"/>
>
> <row ItemID="5" iParentID="4" szSubject="Msg4"/>
>
> And I want an XSLT transformation to get this data in a hierarchical tree
> like that:
>
> 1
>     2
>         3
> 4
>     5
>
> Can you help me?
>
> Thanks in advance....
>
>
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list