Subject: Can anyone help? From: Allen Haws <joeshmoe@xxxxxxxxxx> Date: Wed, 11 Oct 2000 09:58:54 -0700 |
Listers, I've created an extension function (javaclass) and am calling it from within the xsl. <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:java="http://xml.apache.org/xslt/java" version = "1.0"> <xsl:template match="extensiontest"> The return value of the funcion call is : <xsl:value-of select="java:net.unicon.xml.XSLExtFunctions.test()"/> </xsl:template> </xsl:stylesheet> The call works fine if I jar the class and put it in my extension directory of my jdk but it doesn't find the class if I leave it in its classpath directory. I am having to jar the class up with the package directory structure and putting in the extension directory instead of leaving in my classpath. Can anyone tell my why my xsl processor doesn't read my classpath? All Xalan documentation that I have says that it should. I'm processing with Xalan using jdk1.2.2. Thanks -- ******************************************* Allen Haws Unicon Inc. Email: joeshmoe@xxxxxxxxxx Phone: 480.926.2368 ext 343 Direct: 480.558.2445 ******************************************* XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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