Subject: RE: How To Access a param from style sheet From: Scott_Boag@xxxxxxxxx Date: Thu, 19 Oct 2000 13:45:20 -0400 |
The best place to ask questions about the Xalan API and behavior is on the xalan-dev list (mailto:xalan-dev-subscribe@xxxxxxxxxxxxxx, or go to http://xml.apache.org/mail.html). -scott Kay Michael <Michael.Kay@xxxxxxx> To: "'xsl-list@xxxxxxxxxxxxxxxx'" <xsl-list@xxxxxxxxxxxxxxxx> Sent by: cc: (bcc: Scott Boag/CAM/Lotus) owner-xsl-list@mulber Subject: RE: How To Access a param from style sheet rytech.com 10/19/00 06:28 AM Please respond to xsl-list > I am new to XSLT and also to this list. I have a quick > question about accessing parameters from XSL style sheets. I am using Xalan > XSLT processor in my servlet to transform XML into HTML using XSL. I am > able to set the stylesheet param using > > xslProcessor.setStylesheetParam("sortBy", "receiverId"); > I'm not a Xalan expert (!) but I seem to recall that the second parameter is an XPath expresssion, not a string, so you might need to write "'receiverId'". Mike Kay XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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