Subject: <xsl:sort> Q From: mxmodi@xxxxxxxxxxxxxxx Date: Tue, 21 Nov 2000 17:52:14 -0600 |
Hi, I have a simple sort Q. I am trying to sort numbers for a select box in ascending order. After running it through the XSLT processor, what I do get is a sort, however, it is sorting based on the first digit of the number. By doing so, it considers the number "3" to be greater than the number "27". How do I avert this sorting? ANd I cannot make ID as an attribute. Here is a sample XML" <Names> <Name> <Description>abc</Description> <ID>30</ID> </Name> <Name> <Description>aaa</Description> <ID>7</ID> </Name> <Name> <Description>bbb</Description> <ID>27</ID> </Name> <Name> <Description>bbb</Description> <ID>2</ID> </Name> </Names> Sample XSL: ... <xsl:template match="/"> <select name="numberlistbox" size="10"> <xsl:apply-templates select="Names/Name"> <xsl:sort select="ID" /> </xsl:apply-templates> </select> ... </xsl:template> <xsl:template match="Name"> <option> <xsl:value-of select="ID" /> </option> </xsl:template> Result: ID's are: 2 27 30 7 Desired result: 2 7 27 30 Any help is appreciated. Thanks, Maulik XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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