Subject: RE: XML to XML transformation From: Kay Michael <Michael.Kay@xxxxxxx> Date: Wed, 22 Nov 2000 14:31:16 -0000 |
> To begin with, I tried to write an XSL stylesheet that > creates a result document that is the same as the source. > > I found that I don't know how to do it. See section 7.5 of the XSLT spec. There's a simpler way: <xsl:template match="/"> <xsl:copy-of select="."/> </xsl:template> But you can't modify that to make any changes. > The best thing I got was this: > > <xsl:text disable-output-escaping = "yes" ><</xsl:text> > Turn to disable-output-escaping as a last resort only. If you're using it as a beginner then it means you haven't understood the basic principle of the language, which is that you write nodes to the result tree, not tags to the output file. Mike Kay XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
RE: XML to XML transformation, John Power | Thread | RE: XML to XML transformation, Kay Michael |
Re: Is failed key-lookups very slow, (Thorbjoern Ravn And | Date | How to Sort, Group, sub-Total and T, mvictor |
Month |