Subject: Absolute ordering -- determining order when position() won't work From: Ross Bleakney <RossB@xxxxxxxxxxxxxxx> Date: Mon, 4 Dec 2000 14:28:07 -0800 |
Hello, I have XML which consists of elements which are either folders or files: <Folder name="foldera"> <File name="a" /> <Folder name="folderb"> </ Folder> <File name="b" /> <Folder name="folderc"> <File name="c" /> <File name="d" /> </ Folder> </Folder> The order of the folders and files is arbitrary. I have written some XML to list the names of all of the files: <xsl:template name="files_folders"> <xsl:choose> <xsl:when test="self::File"> <xsl:call-template name="files" /> </xsl:when> <xsl:when test="self::Folder"> <xsl:for-each select="./*"> <xsl:call-template name="files_folders" /> </xsl:for-each> </xsl:when> </xsl:choose> </xsl:template> <xsl:template name="files"> <h3> <xsl:value-of select="@name" /> </h3> </xsl:template> What I would like to do, is precede each file name with a number, like so: 1 a 2 b 3 c 4 d If I use position(), then I will get the order of the element in the subtree: 1 a 3 b 1 c 2 d Does anyone have any idea how to solve this problem? Thanks, Ross XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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