Re: [xsl] select following-siblings, but not all of them

Subject: Re: [xsl] select following-siblings, but not all of them
From: Fred Boon <fredboon@xxxxxxxxx>
Date: Tue, 19 Dec 2000 07:08:19 -0800 (PST)
Francis,

your example code helped me flesh out the suggestions
yesterday of Ken Meltsner in his reply to my "creating
XML hierarchy where not existed before??" post.

thank you one, thank you all.

//F


--- Francis Norton <francis@xxxxxxxxxxx> wrote:
> 
> use the following transform:
> 
> <?xml version="1.0" encoding="UTF-8"?>
> <xsl:stylesheet version="1.0"
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
>   <xsl:output method="text" version="1.0"
> indent="yes"/>
>   <xsl:template match="/">
>     <xsl:for-each select="/dataset/name">
>       <xsl:variable name="key" select="."/>
>       <xsl:value-of select="concat(., ' ')"/>
>       <!-- get all following remark elements for
> which this is the
> nearest preceding name -->
>       <xsl:for-each
>
select="following-sibling::remark[count(preceding-sibling::name[1]
> |
> $key) = 1]">
>         <xsl:value-of select="concat(., ' ')"/>
>       </xsl:for-each>
>     </xsl:for-each>
>   </xsl:template>
> </xsl:stylesheet>
> 


__________________________________________________
Do You Yahoo!?
Yahoo! Shopping - Thousands of Stores. Millions of Products.
http://shopping.yahoo.com/

 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list


Current Thread