Subject: [xsl] How to select distinct combined element values From: "Albert Tsun" <albert.tsun@xxxxxxxxxxxx> Date: Thu, 21 Dec 2000 12:06:15 +0800 |
Dear All, I got a problem in getting distinct element group values. XML source: +++++++++++ <match> <date>1-11-2000</date> <team>Brazil</team> <group>A</group> <score>1</score> </match> <match> <date>2-11-2000</date> <team>Brazil</team> <group>A</group> <score>1</score> </match> <match> <date>1-11-2000</date> <team>Brazil</team> <group>B</group> <score>1</score> </match> <match> <date>1-11-2000</date> <team>Argentina</team> <group>A</group> <score>1</score> </match> <match> <date>1-11-2000</date> <team>Argentina</team> <group>A</group> <score>1</score> </match> for distinct team : In XSL, I can use <xsl:variable name="teams" select = "//team[not(.=preceding::team)]"/> to get Brazil Argentina However, if I want to get distinct team, group, that is Brazil A Brazil B Argentina A How can I do it ? would Mike give me some suggestion ? TIA XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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