Subject: RE: [xsl] How to select distinct combined element values From: Kay Michael <Michael.Kay@xxxxxxx> Date: Tue, 2 Jan 2001 11:29:48 -0000 |
> for distinct team : > In XSL, I can use > <xsl:variable name="teams" select = > "//team[not(.=preceding::team)]"/> > to get > Brazil > Argentina > > However, if I want to get distinct team, group, that is > Brazil A > Brazil B > Argentina A > the [not(.=preceding::X)] construct is only useful where the grouping value is the string value of a node. This is because it relies on the implicit "if there exists" semantics of the "=" operator. For grouping on more complex expressions, use the Muenchian technique with a key: see www.jenitennison.com. Alternatively use proprietary extensions such as saxon:distinct(). Mike Kay XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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