Subject: Re: [xsl] Re: Namespace questions From: Ayelet Kotzer <akotzer@xxxxxxxxxxx> Date: Tue, 02 Jan 2001 11:38:56 -0800 |
Hi Dimitri, Can you give me an example. I am not sure where is each of the commands that you mention. For example the line xmlns:m="B" exclude-result-prefixes="m" . Where should it appear ? Thanks, Ayelet Dimitre Novatchev wrote: > Ayelet, > > You can get rid of the namespace declaration on the child nodes by > adding the following to your xsl:stylesheet element: > > xmlns:m="B" exclude-result-prefixes="m" > > Then you'll get in your output: > > <A1>something </A1><A2 att="att1">something </A2> > > However, the top element(s) that declare the namespace will still be > copied with the namespace declaration. So, the result of processing > your fragment will look like this: > > <m:A xmlns:m="B"><A1>something </A1><A2 att="att1">something > </A2></m:A> > > Obviously, you must have a separate template that matches all > m:yourNames elements you'd like to copy without the namespace > declaration on them. Then in this template use xsl:element and > xsl:attribute and specify the local-name(). > > Dimitre. > > Ayelet Kotzer wrote: > > (Desired) Output: > <A > > <A1>something </A1> > <A2 att="att1>something </A2> > </A> > > What I got is something like this: > <A1 xmlns:m="B">something </A1> > <A2 xmlns:m="B" att="att1 >something </A2> > > __________________________________________________ > Do You Yahoo!? > Yahoo! Photos - Share your holiday photos online! > http://photos.yahoo.com/ > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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