Subject: Re: [xsl] Newbie document() question From: David Carlisle <davidc@xxxxxxxxx> Date: Fri, 12 Jan 2001 16:52:44 GMT |
> <xsl:variable name='otherDoc' select='document(MyXml.xml)'/> MyXml.xml is a valid QName so will be evaluated to return all the <myXML.xml> element nodes that are children of the root of document a. This is most likely empty, and anyway isn't what you want:-) <xsl:variable name='otherDoc' select='document("MyXml.xml")'/> is closer, but you don't really need a variable at all. All you need do is copy the identity transformation from the XSL spec and then add one extra template <xsl:template match="some-xpath-that-matches-where-you-want-to-graft"> <xsl:copy-of select='document('MyXml.xml')"/> </xsl:template> David _____________________________________________________________________ This message has been checked for all known viruses by Star Internet delivered through the MessageLabs Virus Control Centre. For further information visit http://www.star.net.uk/stats.asp XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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