Subject: [xsl] xsl, position, template Problem From: "Partho Paul" <uk4u@xxxxxxxxxxxxxxxxxxx> Date: Wed, 31 Jan 2001 11:51:46 +0100 |
I have the following xml given: <Para> Some useful Text <Stretchext>Bla Bla - some usefule thing</Stretchext> Another useful text <Stretchext>Bla Bla - some usefule thing</Stretchext> Further useful text </Para> The Probelm is, how to create a xsl Stylesheet? I used the following: .... <xsl:template match="Para"> <xsl:apply-templates select="//Stretchtext"/> </xsl:template> <xsl:template match="Stretchtext"/> <xsl:value-of select="position()"/> </xsl:template> --------------------------------------------------------- Problem: The problem now is that the function postion() works well, but I don't get the output of the text from the xml File. If I do the following: <xsl:template match="Para"> <xsl:apply-templates /> </xsl:template> I do get the output of the texts, but now the function position() dos not count correctly. So how can I get the output of the text according to its occurance and count the Stretchtext-Tags correctly. Thank you. Partho _______________________________________________________________________ Partho Paul email: uk4u@xxxxxxxxxxxxxxxxxxx Computer science student or: paul@xxxxxxxxx ----------------------------------------------------------------------- Homepage: http://www.partho.de Durga Puja: http://www.uni-karlsruhe.de/~uk4u/durga.html XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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