Subject: Re: [xsl] Seeking XPATH From: David Carlisle <davidc@xxxxxxxxx> Date: Tue, 6 Mar 2001 18:46:55 GMT |
try again. A[ B[@NM = "case1"]/text() = A[B[@NM = "case3"]/text()] ] So that selects A nodes for which the filter is true. B[@NM = "case1"]/text() is the node set of three text nodes { " " , " " , " --- " } but in the right hand side you have the path A which looks for A children of the current A node. I'm not sure quite what you intended, either . or ../A presumably. David _____________________________________________________________________ This message has been checked for all known viruses by Star Internet delivered through the MessageLabs Virus Control Centre. For further information visit http://www.star.net.uk/stats.asp XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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Re: [xsl] Seeking XPATH, David Carlisle | Thread | [xsl] xsl:element question, mjyoungblut |
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