RE: [xsl] How to specify a path to a node in a nodeset using a variable

Subject: RE: [xsl] How to specify a path to a node in a nodeset using a variable
From: "Shakeel Mahate" <shakeelmahate@xxxxxxxxxxx>
Date: Tue, 13 Mar 2001 18:20:16 -0700
From: "Michael Kay" <mhkay@xxxxxxxxxxxx>
>The suggestion was not to concatenate $container and $path, it was to
>concatenate '$container/' and $path, that is to construct a string
>consisting of the string '$container/' followed by (the value of $path
>converted to a string); the resulting string will contain an XPath
>expression which the evaluate() function then evaluates.

I tried it and it works!!!  But it is a mystery what exactly is
saxon:evaluate() doing?

It receives the following argument $container//account/person/@name because
of the concat function.

concat('$container/', $path) where $path is /account/person/@name

Is $container//account/person/@name a valid XPath expression?

I tried looking up the documentation for the saxon:evaluate and
xalan:evaluate() but I couldnt answer the question.

Do I need an extra slash between $container and the $path?

-Shakeel

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