Subject: [xsl] Absolute position From: "Carmelo Montanez" <carmelo@xxxxxxxx> Date: Thu, 15 Mar 2001 04:23:26 -0500 |
Hi all: Does anyone knows how to get the aboslute value of an element within a tree? and by that I mean the order on which it is listed within that tree. Look at the tree below <child1> </child1> <child2> <child2-1> <child2-1-1> <child2-1-1-1> </child2-1-1-1> </child2-1-1> </child2-1> </child2> <child3> <child3-1> </child3-1> </child3> <child4> </child4> </parent> To be more clear I am looking for this type of information "child1" - is number 1 "child2" - is number 2 "child2-1" - is number 3 "child2-1-1" is number 4 "child2-1-1-1" is number 5 "child3" is number 6 "child3-1" is number 7 "child4" is number 8 and so on .... in other words its "absolute position" as you read from to to bottom and I want to know that information when THAT node is the context node in other words if "child6" is the current node I want to know that it is really number 6 as I read. Any ideas? XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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