Subject: [xsl] determine node position From: Kristof Bernaert <kbernaert@xxxxxxxxxxx> Date: Sun, 8 Apr 2001 15:15:37 +0200 |
hi with the value of an attribute i'm trying to determine the node position number of the one element that contains that specific attribute value. I tried already anything like this: <xsl:when test="News/NewsBlock[@LABEL = '4']"><xsl:value-of select="position()"> </xsl:when> but in this case i get always node position 1. how to determine the position towards the whole node-set ? <week> <item ID="monday"/> <item ID="thuesday"/> <item ID="wednesday"/> <item ID="thursday"/> <item ID="friday"/> <item ID="saterday"/> <item ID="sunday"/> </week> I want to now for example on which node position <item ID="thursday"/> is. thx, kb XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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