[xsl] How do I use following right????????? urgent

Subject: [xsl] How do I use following right????????? urgent
From: "Marcus Klinge" <klinge@xxxxxxxxxxxxxxx>
Date: Thu, 12 Apr 2001 13:15:53 +0200
Ok, I have the following code.

Since I need 2 (3,with the bling seperating td) tds in a row, I want to find
out the B2B/RUBRIK/@name of the following
node.  Sadly, this code does not seem to work:

<xsl:template name="mitte">
		<table border="0" width="366" align="center" cellpadding="0"
cellspacing="0">
			</tr>
				<xsl:for-each select="B2B/RUBRIK">
					<xsl:sort select="RUBRIK/NR"/>
					<tr>
					<xsl:variable name="NAME"><xsl:value-of select="@name"/></xsl:variable>
					<xsl:if test="pan:LetpanVar(1,string($NAME))"/>
					<xsl:variable name="RUBRIKEN"
select="pan:load('/b2b/data/%.xml','',-1,false())"/>
					<xsl:if test="position() mod 2 = 1">
						<td width="142" valign="top">
							<xsl:call-template name="linksbalken">
								<xsl:with-param name="titel"><xsl:value-of
select="$NAME"/></xsl:with-param>
							</xsl:call-template>
							<br/>
						<xsl:apply-templates select="$RUBRIKEN" mode="übersicht"/>
						</td>
						<td><img src="http://bilder.fireball.de/bilder/1.gif"; width="8"/></td>
						<td width="142">
						<xsl:variable name="rubi"><xsl:value-of
select="following::B2B/RUBRIK/@name[1]"/></xsl:variable>
						<xsl:if test="pan:LetpanVar(1,string($rubi))"/>
							<xsl:call-template name="rechtsbalken">
								<xsl:with-param name="titel"><xsl:value-of
select="$rubi"/></xsl:with-param>
							</xsl:call-template>
							<br/>
						<xsl:apply-templates select="$RUBRIKEN" mode="übersicht"/>
					 </td>
					</xsl:if>
				</tr>
				</xsl:for-each>
		</table>
	</xsl:template>


Marcus Klinge
Web Producing
----------------------
Karzauninkat Webdesign
Barner Strasse 14
22765 Hamburg
Tel: 040 39834 771
Fax: 040 39834 779


-----Ursprüngliche Nachricht-----
Von: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx
[mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]Im Auftrag von Samuzeau
Pascal
Gesendet: Donnerstag, 12. April 2001 10:47
An: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Betreff: [xsl] How build an Array, N columns, M lines ?


Hi,

So the question is How to build it.

I just want to build an array of pictures. The part of XML is :

<picture number="1">
    <height>128</height>
    <width>128</width>
    <name>X</name>
    <location>Here/</location>
</picture>

... This repeat N times as long as possible. I want to display this in 6
columns max.

Thank

PS


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