[xsl] Transforming XHTML possible?

Subject: [xsl] Transforming XHTML possible?
From: dwight funk <dfunk@xxxxxxxxxxxxxxx>
Date: Fri, 13 Apr 2001 10:20:40 -0500
Is it possible to transform XHTML ?

I have created what I think is a most basic example. The XHTML is by the
standard. The style sheet should merely "copy" the XHTML from input to
output. It looks to me like the xPath queries are not working. I'm using
MSXML3. What am I missing ?  Why doesn't this simple example work ?  Are my
copy templates missing something ?

Dwight Funk
POWERWAY, Inc.


---------------TEST.XML---------------------------------------------------
<?xml version="1.0" encoding="UTF-8"?>

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd";>

<html xmlns="http://www.w3.org/1999/xhtml"; xml:lang="en" lang="en">

	<head>
		<title>Testing Title</title>
	</head>

	<body>
		<p>Test</p>
	</body>

</html>
---------------TEST.XML---------------------------------------------------

---------------TEST.XSL---------------------------------------------------
<?xml version="1.0" encoding="UTF-8"?>

<xsl:stylesheet	xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
version="1.0">

	<xsl:output method="xml" encoding="UTF-8"/>

	<!-- Match the root node -->
	<xsl:template match="/">
		<xsl:apply-templates select="*"/>
	</xsl:template>

	<!-- Handle any node not yet matched -->
	<xsl:template match="*|@*|text()|comment()">
		<xsl:copy>
			<xsl:apply-templates
select="*|@*|text()|comment()"/>
		</xsl:copy>
	</xsl:template>

</xsl:stylesheet>
---------------TEST.XSL---------------------------------------------------
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