Subject: RE: [xsl] changing the order of xml elements when doing XSLT From: "Michael Kay" <mhkay@xxxxxxxxxxxx> Date: Thu, 19 Apr 2001 10:40:21 +0100 |
> i have a need to accomplish the following.. i.e. when doing > an XSLT over an > XML file.. have the output xml be in a specific order that is > NOT the same > as the order in the original XML. Do <xsl:template match="/"> <xsl:apply-templates> <xsl:sort select="name()"/> </xsl:apply-templates> </xsl:template> Mike Kay Software AG > > source.xml > > <?xml version="1.0" encoding="UTF-8"?> > <?xml-stylesheet type="text/xsl" href="mapper.xsl"?> > <record> > <a>1</a> > <b>2</b> > <c>3</c> > </record> > > mapper.xsl > > <?xml version="1.0" encoding="UTF-8"?> > <xsl:stylesheet version="1.0" > xmlns:xsl="http://www.w3.org/1999/XSL/Transform" > xmlns:fo="http://www.w3.org/1999/XSL/Format"> > <xsl:output method="xml" omit-xml-declaration="yes" indent="no"/> > <xsl:template match="/"> > <xsl:apply-templates/> > </xsl:template> > <xsl:template match="record"> > <newrecord><xsl:apply-templates/></newrecord> > </xsl:template> > <xsl:template match="c"> > <CC> > <xsl:value-of select="."/> > </CC> > </xsl:template> > <xsl:template match="a"> > <AA><xsl:value-of select="."/></AA> > </xsl:template> > <xsl:template match="b"> > <BB> > <xsl:value-of select="."/> > </BB> > </xsl:template> > </xsl:stylesheet> > > current output: > > <newrecord > xmlns:fo="http://www.w3.org/1999/XSL/Format"><AA>1</AA><BB>2</ > BB><CC>3</CC>< > /newrecord> > > desired output: > > <newrecord > xmlns:fo="http://www.w3.org/1999/XSL/Format"><CC>3</CC><BB>2</ > BB><AA>1</AA>< > /newrecord> > > any ideas would be highly appreciated.. > > thanks! > > Charlie > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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