Re: [xsl] XSLT FAQ? and really questions

[David Carlisle <davidc@xxxxxxxxx>]

> 	This is a really great example.
actually it's a really bad example. Using disable-output encoding
completely misses all the benefits of using a transformation language
like XSLT which is designed to produce element nodes, not literal text.

I think you want something like

<xsl:stylesheet
   version="1.0"
   xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
>
<xsl:output encoding="utf-8" indent="yes"/>

<xsl:template match="/">
<idsets>                                                                        
        <ID1List>
         <xsl:copy-of select="/records/record/ID1"/>
        </ID1List>
        <ID2List>
         <xsl:copy-of select="/records/record/ID2"/>
        </ID2List>
</idsets>
</xsl:template>

</xsl:stylesheet>

which produces:

BASH.EXE-2.02$ msxsl node.xml nodes.xsl
<?xml version="1.0" encoding="utf-8"?>
<idsets>
<ID1List>
<ID1>123</ID1>
<ID1>345</ID1>
</ID1List>
<ID2List>
<ID2>234</ID2>
<ID2>456</ID2>
</ID2List>
</idsets>


when run in the  EE.

David

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