Subject: Re: [xsl] send 'with-param' determined by test From: "Swen Thuemmler" <Swen.Thuemmler@xxxxxxxxxxxx> Date: Mon, 7 May 2001 08:47:44 +0200 (CEST) |
On Mon, 7 May 2001, Tim Watts wrote: > Hi, > > I would like to send different parameters depending on what XML is available > to the XSLT. > > If the user has already conducted a search, I would like the XSL to refer to > the parameter last used (/document/transient/param[@name = 'from-year']), or > else to use a value diffined by me in the XML > (/document/data/merchant/start-date/@year). > > I have included the code below. > > <xsl:call-template name="date-stripper"> > <xsl:choose> > <xsl:when test="/document/transient/param[@name = 'from-year']"> > <xsl:with-param name="start-date-year" > select="/document/transient/param[@name = 'from-year']" /> > </xsl:when> > <xsl:otherwise> > <xsl:with-param name="start-date-year" > select="/document/data/merchant/start-date/@year" /> > </xsl:otherwise> > </xsl:choose> > > > However when I try to run this I get the following error > > Error [code:235] [URI:file:/stats/search.xsl] [line:5] [node: > element '<xsl:when>'] > XSL element 'when' cannot contain element 'with-param' at this point > > Is there any way to select a param to be sent to a template dependant on a > certain criteria? > > Thank you for your help > > Tim Watts > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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