Subject: RE: [xsl] Using variables in xsl:sort select attribute From: Mike McGraw <mmcgraw@xxxxxxx> Date: Thu, 24 May 2001 12:51:12 -0400 |
Thanks! That worked great. I still don't understand why I couldn't use a variable as the argument of the select attribute though. Anyway, much thanks Mike > -----Original Message----- > From: Adam Turoff [mailto:ziggy@xxxxxxxxx] > Sent: Thursday, May 24, 2001 12:36 PM > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: Re: [xsl] Using variables in xsl:sort select attribute > > > On Thu, May 24, 2001 at 12:01:50PM -0400, Mike McGraw wrote: > > <xsl:template match="customerList"> > > <xsl:variable name="sortby" select="@sortby"> > > > > <xsl:for-each select="person"> > > <xsl:sort select="$sortby"/> > > <tr> > > <td><xsl:value-of select="name" /></td> > > <td><xsl:value-of select="age" /></td> > > </tr> > > </xsl:for-each> > > > > </xsl:template> > > > > However, this doesn't work. The parser ignores the sort > instruction. Am I > > permitted to use a variable as the argument for the select > attribute of the > > sort? > > It looks like select="$sortby" is a constant expression, so > the results > are in their original order. > > Try this instead (yes, it's ugly, but it sorts): > > <xsl:for-each select="person/*[name() = $sortby]"> > <xsl:sort select="."/> > <tr> > <td><xsl:value-of select="../name" /></td> > <td><xsl:value-of select="../age" /></td> > </tr> > </xsl:for-each> > > Z. > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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