Subject: RE: [xsl] Problem in making choices using <xsl:choose> From: "Michael Kay" <mhkay@xxxxxxxxxxxx> Date: Fri, 1 Jun 2001 11:40:26 +0100 |
Weird. Can you show us a complete stylesheet that demonstrates the problem, and tell us which processor you're using? Mike Kay Software AG > -----Original Message----- > From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx > [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]On Behalf Of Sreekanth > Pallavoor > Sent: 01 June 2001 03:37 > To: XSL-List@xxxxxxxxxxxxxxxxxxxxxx > Subject: [xsl] Problem in making choices using <xsl:choose> > > > Hi, > > I am new to XSLT. I am writing one XSLT program, where I need to print > different output depending upon different conditions. But the > code which > checks for different conditions, doesn't seem to be working properly. > The relevant part of code is given below. Here I have got a variable > "state" getting set to some state code which comes from some external > source. If it's value is AZ, I want to print "Arizona" and if > it's value > is anything else then I want to print "Other". The result I am getting > is, it always prints "Arizona" even if $state is set to > something other > than "AZ". (To double-check, I am printing the $state value > also in the > output. Even if it is CA, the output I still get is "CA > Arizona" and not > "CA Other"). > > Can someone tell me what could be the reason. > > Thanks. > -- Sreekanth > > <xsl:template match="headline"> > <xsl:choose> > <xsl:when test="contains($state,'AZ')"> > <font face="{$headline-font}" > size="{$headline-size}"><xsl:value-of select="$state"/> > Arizona </font> > </xsl:when> > <xsl:otherwise> > <font face="{$headline-font}" > size="{$headline-size}"><xsl:value-of select="$state"/> Other </font> > </xsl:otherwise> > </xsl:choose> > </xsl:template> > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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