Subject: [xsl] Why is my xsl:param empty? (passed with xsl_with-param) From: Rene de Vries <RdVries@xxxxxxxxxxx> Date: Fri, 15 Jun 2001 11:04:54 +0200 |
I'm playing around with xsl:with-param and xsl:param, but I cant get my param passed. What do I do wrong? I expect: $trythis: 8 $trythis: 8 but I get $trythis: $trythis: xml: <root> <x>bla</x> <x>blabla</x> </root> xsl: <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:template match="/"> <xsl:apply-templates> <xsl:with-param name="trythis" select="8"/> </xsl:apply-templates> </xsl:template> <xsl:template match="x"> <xsl:param name="trythis"/> <p> $trythis: <xsl:value-of select="$trythis"/> </p> </xsl:template> </xsl:stylesheet> Greetings Rene { @ @ } ^ \__/ "You don't need eyes to see, you need vision!" XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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