Subject: [xsl] pls help me on XML-XSLt Tag Display From: Maricar Gold <cow8th@xxxxxxxxx> Date: Wed, 27 Jun 2001 02:01:56 -0700 (PDT) |
Hi, I am currently coding an XSLt to transform an XML document to another XML with different formatting. I cannot seem to know how to remove certain tags from displaying when there is no value. For example, if a values exist for ListofDescription from the source document, the output should display as: <ExampleTag>Example</ExampleTag> <ListofDescription> <DescInfo> <DescriptionID>Color</DescriptionID> <Description>Red</Description> </DescInfo> <DescInfo> <DescriptionID>Height</DescriptionID> <Description>57</Description> </DescInfo> </ListofDescription> <FinalTag>Final</FinalTag> (Element DescInfo can have 0 to n occurrences. These are retrieved by xsl:for-each loop or apply-template statement. Element ListofDescription can have 0 or 1 occurence, depending on the existence of DescInfo.) However, if no value exists for DescInfo from the source, then the <ListofDescription> tag should not appear at all: <ExampleTag>Example</ExampleTag> <FinalTag>Final</FinalTag> Is this possible? What syntax / logic should I use? I would very much appreciate any help from you guys. Thank you. Cow __________________________________________________ Do You Yahoo!? Get personalized email addresses from Yahoo! Mail http://personal.mail.yahoo.com/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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