Subject: RE: [xsl] Count all the following nodes of a perticular parent From: "Michael Kay" <mhkay@xxxxxxxxxxxx> Date: Fri, 29 Jun 2001 10:42:51 +0100 |
> how can i count following nodes of a perticular node, with a > perticular parent. If the context node is the second <branch>, then count(following-sibling::*) (which I think is what I suggested when you first raised the question) will return 2. Note that this is actually counting elements, not nodes. Mike Kay Software AG > the xml is something like that: > <root> > <branch> > <subBranch> > . > . > <branch> > <subBranch> > . > . > <branch_anotherType> > > <subBranch> > . > <branch_anotherType> > > <subBranch> > . > . > </root> . > > actually i want to count how many child nodes exists after > 2nd <branch> > element. > i expected to have 2 as the result > > thank you. > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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