Subject: RE: [xsl] node-set From: "Michael Kay" <mhkay@xxxxxxxxxxxx> Date: Mon, 2 Jul 2001 10:41:45 +0100 |
> Im having problems selecting a nodeset with the node-set() in > msxml3. > <xsl:variable name="peerFullPath" > select="concat($peerPath,'/',$quarterYear)" /> > <td><xsl:value-of select="msxsl:node-set($peerFullPath)/peer1" /></td> The xx:node-set() function converts a result tree fragment to a node-set. It doesn't take a string containing an XPath expression and evaluate that expression. For that you need something like the saxon:evaluate() extension function. You can simulate this in MSXML3 by calling selectNodes() within a JScript extension. Mike Kay Software AG XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
Re: [xsl] node-set, Trevor Nash | Thread | Re: RE: [xsl] node-set, Dimitre Novatchev |
RE: [xsl] [XSL] Custom DocumentHand, Michael Kay | Date | RE: [xsl] sorting and grouping - ca, Michael Kay |
Month |