Subject: Re: [xsl] given @id="1.2.3" .... -1 || +1 to the "3" in @id?? From: Jeni Tennison <mail@xxxxxxxxxxxxxxxx> Date: Tue, 3 Jul 2001 09:43:30 +0100 |
Hi Anthony, > My main concern here is the syntax of getting the substring after > the last '.' in a string: ie - if id="1.22.33" or "1.2.3", how do > specify the character position of the last '.', since it will not > always be the 4th or 5th character in the string. I don't think anyone's shown you a recursive template to do this, so here's one: <xsl:template name="substring-after-last"> <xsl:param name="string" /> <xsl:param name="delimiter" select="'.'" /> <xsl:choose> <xsl:when test="not(contains($string, $delimiter))"> <xsl:value-of select="$string" /> </xsl:when> <xsl:otherwise> <xsl:call-template name="substring-after-last"> <xsl:with-param name="string" select="substring-after($string, $delimiter)" /> <xsl:with-param name="delimiter" select="$delimiter" /> </xsl:call-template> </xsl:otherwise> </xsl:choose> </xsl:template> Cheers, Jeni --- Jeni Tennison http://www.jenitennison.com/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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