Subject: Re: [xsl] Re: RE: Re: RE: Re: XPath riddle From: Wendell Piez <wapiez@xxxxxxxxxxxxxxxx> Date: Thu, 05 Jul 2001 11:54:11 +0100 |
Now, if I understand you well, you want every D/C, for which the first ancestor from
a given list of ancestors (the list of elements defining D and its child C as
descendents) to be "A" and nothing else.
Then this is returned by:
//D/C[name(ancestor::*[name()='A' or name()='F'][1])='A']
Cheers, Wendell
====================================================================== Wendell Piez mailto:wapiez@xxxxxxxxxxxxxxxx Mulberry Technologies, Inc. http://www.mulberrytech.com 17 West Jefferson Street Direct Phone: 301/315-9635 Suite 207 Phone: 301/315-9631 Rockville, MD 20850 Fax: 301/315-8285 ---------------------------------------------------------------------- Mulberry Technologies: A Consultancy Specializing in SGML and XML ======================================================================
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