Subject: RE: [xsl] How to sort a nodeset referenced by a variable? From: "Michael Kay" <mhkay@xxxxxxxxxxxx> Date: Thu, 5 Jul 2001 17:40:52 +0100 |
> So <xsl:sort select="secondelement" /> would work as well (and be a > teeny-tiny bit faster). It might save two microseconds in parsing the XPath expression, but I think you can take it as read that any respectable XSLT engine will reduce xxx and ./xxx to the same internal representation. Actually I think ./xxx is quite nice for extra clarity. Mike Kay XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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