Subject: RE: [xsl] Sorting a NodeSet Contained Within a Variable From: Bryan Tulloch <b.tulloch@xxxxxxxxxxxxx> Date: Wed, 11 Jul 2001 18:04:28 +0100 |
Oliver, Thanks for your guidance, but this isn't working 100% for me. I can sort the node-set if it is comprised purely of nodes from my xml source tree, but not if it consists entirely of the results of a series of calculations (using count()) done on nodes from the source tree. In other words, I want to put those results into a nodeset and sort them. Bryan -----Original Message----- From: Oliver Becker [mailto:obecker@xxxxxxxxxxxxxxxxxxxxxxx] Sent: Tuesday, July 10, 2001 12:14 PM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: Re: [xsl] Sorting a NodeSet Contained Within a Variable Hi Bryan, > I have a variable that constitutes a nodeset; is it possible to sort a > variable nodeset? Well, you can't sort a node-set because sets are unordered. ;-) What you can do is to process the nodes of a set in a specific order. > I ask because I have not been able to get this to work > (although I can sort nodesets that are not variables). This isn't different from any other expression that evaluates to a node-set. Just do either <xsl:apply-templates select="$set"> <xsl:sort .... /> </xsl:apply-templates> or <xsl:for-each select="$set"> <xsl:sort .... /> .... </xsl:for-each> Hope that helps, Oliver /-------------------------------------------------------------------\ | ob|do Dipl.Inf. Oliver Becker | | --+-- E-Mail: obecker@xxxxxxxxxxxxxxxxxxxxxxx | | op|qo WWW: http://www.informatik.hu-berlin.de/~obecker | \-------------------------------------------------------------------/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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