[xsl] changing the nodeset

Subject: [xsl] changing the nodeset
From: Michael Schäfer <MSchaefer@xxxxxxxxxxxx>
Date: Thu, 12 Jul 2001 17:00:04 +0200
Hello,

I process a XML-doc, which contains several <EL1>-elements and
<EL2>-elements and so on. The processing adds numbers as elements to the
new tree.

Now I want to start with numbers, I load from another xml-file, let's
say calld start.xml
In the root of the target I want to add a entity, which contains
elements for all counted elements with the occurrences + the start
values.
So I try

<xsl:template match="/ROOT">
	<!-- now I am in the root-node -->
	<xsl:copy>
		<!-- I copy the root-node and all them children -->
		<xsl:apply-templates select="node()|@*" />

		<!-- now I create a new entity -->
		<xsl:element name="START">
			<!-- I process the nodes in document start.xml
-->
			<xsl:for-each
select="document('start.xml')/START/*">
				<!-- Now my context is a child of
start.xml/START -->
				<!-- I add a new element with the name
of the current node -->
				<xsl:element name="{name()}">
					<!-- and now I want to add the
content of context-node with the occurences of th original doc -->
					<!-- so I have to change context
but how ? -->
					<xsl:value-of
select="number(.)+count(//name())/">
				</xsl:element>
			</xsl:for-each>
		</xsl:element>
	</xsl:copy>
</xsl:template>





Mit freundlichen Grüßen
Michael Schäfer

---------------------------------------------------------------
Dipl.-Ing. Michael Schäfer
e-business

Pfeil GmbH
Obertorstr. 4-6
66111 Saarbrücken 

Tel.: 06 81/3 79 85-30
Fax: 06 81/3 79 85-13

e-Mail: mschaefer@xxxxxxxxxxxx
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